Đề thi Giữa kì 2 Toán 12 năm 2024-2025 trường THPT Thanh Bình 1 (Đồng Tháp)

$\dfrac{2304}{5}$

$56\pi$

$\dfrac{2309}{5}\pi$

54

$7 \cos x + C$

$-\cos x + C$

$-7 \cos x + C$

$7 \sin x + C$

$S=\int\limits_{-2}^{0} f(x) dx$

$S = \pi \int\limits_{-2}^{0} [f(x)]^2 dx$

$S=\int\limits_{-2}^{0} |f(x)| dx$

$S = \pi \int\limits_{-2}^{0} f(x) dx$

$\dfrac{x^{9}}{\ln 9} + C$

$\dfrac{9^{x}}{\ln 9} + C$

$\dfrac{9^{x}}{9} + C$

$x^{9} \ln 9 + C$

-59

-3

57

21

$\dfrac{4}{x^2} + C$

$3x + \dfrac{4}{x^2} + C$

$3x - 4 \ln|x| + C$

$3x + \ln|x| + C$

$F(x) = \dfrac{5x^{4}}{4} + \dfrac{x^{3}}{3} - \dfrac{3x^{2}}{2} + 10$ .

$F(x) = \dfrac{5x^{4}}{4} + \dfrac{x^{3}}{3} + \dfrac{3x^{2}}{2} + 10$ .

$F(x) = \dfrac{5x^{4}}{4} + \dfrac{x^{3}}{3} - \dfrac{3x^{2}}{2} + 8x + 40$ .

$F(x) = \dfrac{5x^{4}}{4} + \dfrac{x^{3}}{3} - \dfrac{3x^{2}}{2} + 40$ .

-14 .

95 .

14 .

-24 .

$5x + C$ .

$\dfrac{5x}{2} + C$ .

$5x^{2} + C$ .

$C$ .