Đề thi Học kì 2 Toán 12 năm 2025-2026 trường THPT Xuyên Mộc (TP.HCM)

ln7.

ln3.

$1+\dfrac{1}{2}\ln7$.

$1+\ln7$ .

$3x - y + 4z - 11 = 0$ .

$x + 2y - 3z - 13 = 0$ .

$3x - y + 4z + 11 = 0$ .

$3x - y + 4z + 13 = 0$ .

$\dfrac{3}{5}$ .

$\dfrac{63}{256}$ .

$\dfrac{21}{80}$ .

$\dfrac{9}{16}$ .

$S=\pi \int_a^b \lvert f(x)-g(x) \rvert dx$ .

$S=\int_a^b [f(x)-g(x)]dx$ .

$S=\int_a^b \lvert f(x)-g(x) \rvert dx$ .

$S= \Bigl \lvert \int_a^b [f(x)-g(x)]dx \Bigr \rvert$ .

0.6 .

0,15 .

0.18 .

0,3 .

$\dfrac{25\sqrt{14}}{14}$

$\sqrt{14}$

$\dfrac{27\sqrt{14}}{14}$

$\sqrt{3}$

$I(2;3;-1)$ .

$I(2;-1;3)$ .

$I(2;-3;1)$ .

$I(-2;1;-3)$ .

$S=\pi \displaystyle\int_ a^b | f(x)-g(x) | \mathrm{d}x$

. $S=\int_ a^b | f(x)-g(x) | \mathrm{d}x$

. $S=\left| \displaystyle\int_ a^b \left[f(x)-g(x)\right]\mathrm{d}x \right|$

. $S=\displaystyle\int_ a^b \left[f(x)-g(x) \right]\mathrm{d}x$

2

-8

8

-2

$(x-1)^2+(y-2)^2+(z+1)^2=26$

$(x-2)^2+(y+1)^2+(z-3)^2=26$

$(x+2)^2+(y-1)^2+(z+3)^2=26$

$(x-2)^2+(y+1)^2+(z-3)^2=\sqrt{26}$

$\cos \varphi=\dfrac{|a_1a_2+b_1b_2+c_1c_2|}{\sqrt{a_1^2+b_1^2+c_1^2}+\sqrt{a_2^2+b_2^2+c_2^2}}$

$\cos \varphi=\dfrac{|a_1a_2+b_1b_2+c_1c_2|}{\sqrt{a_1^2+b_1^2+c_1^2} \cdot \sqrt{a_2^2+b_2^2+c_2^2}}$

$\sin \varphi=\dfrac{|a_1a_2+b_1b_2+c_1c_2|}{\sqrt{a_1^2+b_1^2+c_1^2} \cdot \sqrt{a_2^2+b_2^2+c_2^2}}$

$\cos \varphi=\dfrac{a_1a_2+b_1b_2+c_1c_2}{\sqrt{a_1^2+b_1^2+c_1^2}\sqrt{a_2^2+b_2^2+c_2^2}}$

$P(A|B)=\dfrac{P(A).P(B|A)}{P(B)}$

$P(A|B)=\dfrac{P(A)}{P(B)}$

$P(A|B)=\dfrac{P(B).P(B|A)}{P(A)}$

$P(A|B)=\dfrac{P(AB).P(A)}{P(B)}$