Đề thi Giữa kì 2 Toán 12 năm 2024-2025 trường chuyên Lương Thế Vinh (Đồng Nai)

$\dfrac{1}{2}$

$\dfrac{2}{3}$

$\dfrac{1}{3}$

$-\dfrac{1}{2}$

$\left\{ \begin{array}{l} x = 1 + t \\ y = t \quad (t \in \mathbb{R}) \\ z = 1 - t \end{array} \right.$

$\left\{ \begin{array}{l} x = 1 + 2t \\ y = 2t \quad (t \in \mathbb{R}) \\ z = 1 + t \end{array} \right.$

$\left\{ \begin{array}{l} x = 1 + t \\ y = t \quad (t \in \mathbb{R}) \\ z = 1 + t \end{array} \right.$

$\left\{ \begin{array}{l} x = \mathbf{1 - t} \\ y = t \quad (t \in \mathbb{R}) \\ z = 1 + t \end{array} \right.$

$f(3) = 7$.

$f(3) = 3$.

$f(3) = 4$.

$f(3) = 8$.

$x + y - z = 0.$

$x + y - z - 1 = 0.$

$3x + y + z - 4 = 0.$

$x - y + 3z - 4 = 0.$

$f(x) = -3 \cos x + 2 \sin x.$

$f(x) = 3 \cos x - 2 \sin x + 3.$

$f(x) = - \cos x + \sin x.$

$f(x) = -3 \cos x + 2 \sin x - 1.$

$\vec{n}(1;1;0).$

$\vec{n}(1;1;1).$

$\vec{n}(0;1;0).$

$\vec{n}(0;0;1).$

$N(4;0;\mathbf{-1}).$

$Q(-2;-4;7).$

$M(1;-2;3).$

$P(7;2;1).$

13.

29.

21.

9.

trùng nhau.

vuông góc nhau.

cắt nhau nhưng không vuông góc nhau.

song song nhau.

$\dfrac{2^{x+5}}{\ln 2} + C.$

$\dfrac{2^x}{\ln 2} + C.$

$- \dfrac{2^{x+5}}{\ln 2}.$

$2^x.$