Đề thi Giữa kì 2 Toán 12 năm 2025-2026 trường THPT B Trần Hưng Đạo (Ninh Bình)

$2x - y + 3z - 4 = 0$

$2x - y + 3z + 9 = 0$

$x - 2y - 4 = 0$

$2x - y + 3z + 4 = 0$

$\pi (e^2 + 1)$

$\pi (e^2 - 1)$

$\dfrac{\pi}{2} (e^2 - 1)$

$\dfrac{\pi}{2} (e^2 + 1)$

$f(x) = \dfrac{x^4}{3} + e^x$

$f(x) = \dfrac{x^4}{12} + e^x$

$f(x) = 3x^2 + e^x$

$f(x) = x^2 + e^x$

1

-12

12

7

$\sqrt{3}$

$3 \sqrt{2}$

$\dfrac{9 \sqrt{2}}{2}$

3

$\vec{n} = (1;1;2)$

$\vec{n} = (1;1;-2)$

$\vec{n} = (2;2;1)$

$\vec{n} = (2;2;-1)$

$\int f(x) dx = 3 \sin x - \dfrac{3^x}{\ln 3} + C$

$\int f(x) dx = -3 \sin x - \dfrac{3^x}{\ln 3} + C$

$\int f(x) dx = 3 \sin x + \dfrac{3^x}{\ln 3} + C$

$\int f(x) dx = -3 \sin x + \dfrac{3^x}{\ln 3} + C$

$\int_a^b f(x)\mathrm{d}x=-\int_b^a f(x)\mathrm{d}x$

$\int_a^b f'(x)\mathrm{d}x=0$

$\int_a^b f(x)\mathrm{d}x=\int_a^c f(x)\mathrm{d}x+\int_c^b f(x)\mathrm{d}x, \forall c \in \mathbb{R}$

$\int_a^b f(x)\mathrm{d}x=\int_a^b f(t)\mathrm{d}t$

3

$\dfrac{3}{2}$

$\dfrac{11}{6}$

$\dfrac{9}{2}$

$2x-4y+4z-50=0$

$2x-4y+4z-14=0$ hoặc $2x-4y+4z-50=0$

$2x-4y+4z-14=0$

$2x-4y+4z+14=0$ hoặc $2x-4y+4z-50=0$