Đề thi Học kì 2 Toán 10 năm 2024-2025 trường THPT Ngô Quyền (Đà Nẵng)

A. $\left\{\begin{matrix}a < 0 \\ \Delta \leq 0\end{matrix}\right.$

B. $\left\{\begin{matrix}a > 0 \\ \Delta < 0\end{matrix}\right.$

C. $\left\{\begin{matrix}a < 0 \\ \Delta < 0\end{matrix}\right.$

D. $\left\{\begin{matrix}a > 0 \\ \Delta > 0\end{matrix}\right.$

A. $x=2$.

B. $x=1$.

C. $x=-2$.

D. $x=-3$ .

A. $\vec{n_1} = (4;5)$.

B. $\vec{n_2} = (-8;-10)$.

C. $\vec{n_3} = (4;-5)$.

D. $\vec{n_4} = \left(\dfrac{4}{3};\dfrac{5}{3}\right)$

$\dfrac{4}{5}$.

$2$.

$\dfrac{2}{5}$.

$\dfrac{4}{25}$.

$I\left(-2;4\right);R=16$.

$I\left(2;-4\right);R=16$.

$I\left(-2;4\right);R=4$.

$I\left(2;-4\right);R=4$.

$\dfrac{x^2}{5}-\dfrac{y^2}{4}=-1$.

$\dfrac{x^2}{25}+\dfrac{y^2}{16}=1$.

$\dfrac{x^2}{16}+\dfrac{y^2}{9}=-1$.

$\dfrac{x^2}{8}-\dfrac{y^2}{6}=1$.

$m+n$ (cách thực hiện).

$m.n$ (cách thực hiện).

$m-n$ (cách thực hiện).

$m^n$ (cách thực hiện).

$A_n^k=\dfrac{n!}{\left(n-k\right)!}$.

$A_n^k=\dfrac{n!}{\left(n-k\right)!k!}$.

$C_n^k=\dfrac{n!}{\left(n-k\right)!k!}$.

$C_n^k=\dfrac{n!}{\left(n-k\right)!}$.

3.

6.

5.

4.

$0 \le P\left(A\right) \le 1$.

$P\left(A\right)=1 \iff A=\varnothing$.

$P\left(\overline{A}\right)=1-P\left(A\right)$.

$P\left(A\right)=\dfrac{n\left(A\right)}{n\left(\Omega\right)}$.