Đề thi Học kì 1 Toán 10 năm 2023-2024 trường THPT Quế Sơn (Quảng Nam)

$\forall x \in \mathbb{N}: x^2 - 2 > 0$.

$\boldsymbol{\exists x \in \mathbb{N}: x^2 - 2 \geq 0}$.

$\boldsymbol{\exists x \in \mathbb{N}: x^2 - 2 > 0}$.

$\forall x \in \mathbb{N}: x^2 - 2 \geq 0$.

15 là số nguyên tố.

15 chia hết cho 7.

$\forall x \in \mathbb{R} : x^2 > 0$.

$\boldsymbol{\exists x \in \mathbb{N}: x > 2}.$

$M \cap N = [0;1)$ .

$M \cap N = \varnothing$ .

$M \cap N = (0;1]$ .

$M \cap N = (-2;5)$ .

$\dfrac{1}{x} - 5y \geq 1$ .

$\boldsymbol{5x - 2y \geq 3}$ .

$\dfrac{5}{x} - \dfrac{2}{y} < 3$ .

$3x - y^2 \geq -5$ .

$S = 2a.b \sin C$ .

$S = \dfrac{a.b.c}{4r}$ .

$\boldsymbol{\dfrac{b}{\sin B} = 2R}$ .

$S = p.R$ .

$AB$ .

$\boldsymbol{\overrightarrow{AB}}$ .

$\left|\overrightarrow{AB}\right|$ .

$\overrightarrow{BA}$ .

A. 3

B. 6

C. 4

D. 2

A. $\bar{AD} = \bar{CB}$

B. $\bar{AB} = \bar{BC}$

$C. \bar{AB} = \bar{AD}$.

$D. \bar{AB} = \bar{DC}.$

A. $\bar{BC} + \bar{CA} = \bar{AB}$.

B. $\bar{CA} + \bar{BC} = \bar{BA}$.

C. $\bar{CA} - \bar{CB} = \bar{BA}$.

D. $\bar{BA} + \bar{AC} = \bar{BC}$

A. $\bar{BC} = 3 \bar{AB}$

B. $\bar{AB} = -3 \bar{CA}$

C. $\bar{BC} = -2 \bar{BA}$

D. $\bar{AC} = -4 \bar{AB}$

A. $\bar{MA} + \bar{MB} = \bar{MI}$

B. $\bar{MA} + \bar{MB} = 3 \bar{MI}$

C. $\bar{MI} = \frac{1}{2} (\bar{MA} + \bar{MB})$

D. $\bar{MA} + \bar{MB} = -2 \bar{MI}$

A. $\bar{GA} + \bar{GB} + \bar{GC} = \bar{AB}$

B. $\bar{GA} + \bar{GB} + \bar{GC} = \bar{0}$

C. $\bar{GA} + \bar{GB} = \bar{GC}$

D. $\bar{GA} + \bar{GB} + \bar{GC} = \bar{AC}$

A. $\bar{GA} = 2 \bar{GI}$

B. $\bar{IG} = -\frac{1}{3}\bar{IA}$

C. $\bar{GB} + \bar{GC} = 2 \bar{GI}$

D. $\bar{GB} + \bar{GC} = \bar{GA}$

A. $\bar{j} = (0;0)$

B. $\bar{j} = (0;1)$

C. $\bar{j} = (1;0)$

D. $\bar{j} = (1;1)$

A. $\bar{a} = (-1;-4)$

B. $\bar{a} = (4; -1)$

C. $\bar{a} = (-4;1)$

D. $\bar{a} = (-1;4)$

A. $\bar{c} = (-1; -4)$

B. $\bar{c} = (5; 12)$

C. $\bar{c} = (2;5)$

D. $\bar{c} = (2;6)$

A. $A' (-2; -1)$

B. $A' (1; 2)$

C. $A' (-2; 1)$

D. $A' (2; -1)$

A. $\bar{MN} = (1;1)$

B. $\bar{MN} = (2; 2)$

C. $\bar{MN} = (6; 8)$

D. $\bar{MN} = (-6; -8)$

A. $I(4; 4)$

B. $I(2; 2)$

C. $I(0; -10)$

D. $I(0; 10)$

$D(4; 3)$

$D(3; 4)$

$D(4; 4)$

$D(8; 6)$

$\vec{a} \cdot \vec{b} = 1$

$\vec{a} \cdot \vec{b} = 12$

$\vec{a} \cdot \vec{b} = 7$

$\vec{a} \cdot \vec{b} = 26$

0°

90°

180°

60°

$(0;3)$

$(0;-3)$

$(-1;2)$

$(3;4)$

$\Delta_a = \left|a - \overline{a}\right|$

$\Delta_a = \left|a + \overline{a}\right|$

$\Delta_a = \left|a \overline{a}\right|$

$\Delta_a = \left|\dfrac{a}{\overline{a}}\right|$

[1229; 1239]

[1234; 1239]

[1229; 1234]

(1229; 1234)

$M_e = 16$

$M_e = 17$

$M_e =18$

$M_e=17,5$