13 Bài tập tổng hợp Toán 8 Kết nối tri thức Chương 2

$\left(3y+\dfrac{1}{3}\right)^3.$

$\left(3y-\dfrac{1}{3}\right)^3.$

$\left(\dfrac{1}{3}-3y\right)^3.$

$\left(-\dfrac{1}{3}-3y\right)^3.$

$4x^2-9.$

$2x^2-3.$

$4x^2+9.$

$4x^2+12x+9.$

2xy

xy

-2xy

$\dfrac{1}{2}xy.$

4ab

-4ab

0

2b²

$\left(x-1\right)\left(x^2+x+1\right)=x^3-1$

$\left(x-1\right)\left(x+1\right)=1-x^2.$

$\left(x-1\right)\left(x+1\right)=x^2+1.$

$\left(x-1\right)\left(x^2+x+1\right)=1-x^2.$

$27+27x+9x^2+x^3=\left(3+x\right)^3.$

$x^3-3x^2+3x-1=\left(1-x\right)^3.$

$1-2y+y^2=-\left(y-1\right)^2.$

$1-x^2y^4=-\left(1-xy^2\right)\left(1+xy^2\right)$

0

$2y^3$

2xy

$2x^3.$

$\left(a+b\right)^2-\left(a-b\right)^2=4ab.$

$\left(a+b\right)^2+\left(a-b\right)^2=2\left(a^2+b^2\right)$

$\left(-a-b\right)^2=-\left(a+b\right)^2.$

$\left(-a-b\right)\left(-a+b\right)=a^2-b^2.$

$A=x^2-x-6.$

$B=x^2+x-2.$

$C=x^2-x+1.$

$D=x^2+6x-1.$