Trắc nghiệm Bài 17: Tính chất đường phân giác của tam giác Toán 8

cao

phân giác của một góc

trung tuyến

trung trực

$\frac{{DC}}{{DB}} = \frac{{AB}}{{AC}}$

$\frac{{DC}}{{AC}} = \frac{{AB}}{{DB}}$

$\frac{{AB}}{{BD}} = \frac{{DC}}{{AC}}$

$\frac{{DC}}{{BD}} = \frac{{AC}}{{AB}}$

$\frac{x}{y} = \frac{7}{{15}}$

$\frac{x}{y} = \frac{8}{{15}}$

$\frac{x}{y} = \frac{{11}}{{15}}$

$\frac{x}{y} = \frac{4}{{15}}$

$\frac{4}{5}$

$\frac{5}{4}$

$\frac{3}{4}$

$\frac{4}{3}$

$BD \lt DC$

$BD \gt DC$

$BD = DC$

Không so sánh được

$x = 12$

$x = \frac{{34}}{5}$

$x = \frac{{37}}{5}$

$x = \frac{{36}}{5}$

$BD = \frac{3}{4}DC$

$BD = \frac{2}{3}DC$

$BD = \frac{1}{3}DC$

$BD = \frac{1}{2}DC$

$\frac{{{S_{ABD}}}}{{{S_{ADC}}}} = \frac{5}{6}$

$\frac{{{S_{ABD}}}}{{{S_{ADC}}}} = \frac{4}{5}$

$\frac{{{S_{ABD}}}}{{{S_{ADC}}}} = \frac{2}{3}$

$\frac{{{S_{ABD}}}}{{{S_{ADC}}}} = \frac{3}{4}$

$\frac{{EC}}{{EA}} = \frac{1}{3}.\frac{{DM}}{{DA}}$

$\frac{{EC}}{{EA}} = 3\frac{{DM}}{{DA}}$

$\frac{{EC}}{{EA}} = 2\frac{{DM}}{{DA}}$

$\frac{{EC}}{{EA}} = \frac{1}{2}.\frac{{DM}}{{DA}}$

$\frac{4}{5}$

$\frac{7}{8}$

$\frac{3}{4}$

$\frac{2}{3}$

3cm

6cm

9cm

12cm

$AB = 12cm,BC = 9cm,AC = 6cm$

$AB = 6cm,BC = 12cm,AC = 9cm$

$AB = 6cm,BC = 9cm,AC = 12cm$

$AB = 12cm,BC = 6cm,AC = 9cm$

${S_{AMD}} = \frac{{n + m}}{{3\left( {m - n} \right)}}S{ _{ABC}}$

${S_{AMD}} = \frac{{n - m}}{{3\left( {m + n} \right)}}S{ _{ABC}}$

${S_{AMD}} = \frac{{n + m}}{{2\left( {m - n} \right)}}S{ _{ABC}}$

${S_{AMD}} = \frac{{n - m}}{{2\left( {m + n} \right)}}S{ _{ABC}}$

$AC \approx 12,98cm$

$AC \approx 12,97cm$

$AC \approx 12,88cm$

$AC \approx 12,87cm$

$\frac{{{S_{ADE}}}}{{{S_{ABC}}}} = \frac{3}{{11}}$

$\frac{{{S_{ADE}}}}{{{S_{ABC}}}} = \frac{2}{{11}}$

$\frac{{{S_{ADE}}}}{{{S_{ABC}}}} = \frac{4}{{11}}$

$\frac{{{S_{ADE}}}}{{{S_{ABC}}}} = \frac{5}{{11}}$

$\frac{3}{5}$

$\frac{3}{4}$

$\frac{3}{7}$

$\frac{4}{7}$

$\frac{{DI}}{{DA}} + \frac{{EI}}{{EB}} + \frac{{FI}}{{FC}} = \frac{1}{2}$

$\frac{{DI}}{{DA}} + \frac{{EI}}{{EB}} + \frac{{FI}}{{FC}} = 2$

$\frac{{DI}}{{DA}} + \frac{{EI}}{{EB}} + \frac{{FI}}{{FC}} = 1$

Đáp án khác

$x = 13$

$x = 12$

$x = 14$

Cả A, B, C đều sai

$\frac{5}{6}$

$\frac{1}{3}$

$\frac{1}{2}$

$\frac{3}{4}$

$\frac{{DB}}{{DC}}.\frac{{EC}}{{EA}}.\frac{{FA}}{{FB}} = \frac{1}{2}$

$\frac{{DB}}{{DC}}.\frac{{EC}}{{EA}}.\frac{{FA}}{{FB}} = 1$

$\frac{{DB}}{{DC}}.\frac{{EC}}{{EA}}.\frac{{FA}}{{FB}} = 2$

$\frac{{DB}}{{DC}}.\frac{{EC}}{{EA}}.\frac{{FA}}{{FB}} = \frac{1}{3}$

$DI = \frac{4}{5}IE$

$DI = \frac{3}{4}IE$

$DI = \frac{2}{3}IE$

$DI = IE$