Đề giữa kỳ 2 Toán 11 năm 2024 – 2025 trường THPT Ngọc Lặc – Thanh Hóa

$a^{\dfrac{1}{15}}$.

$a^{15}$.

$a^{\dfrac{3}{5}}$.

$a^{\dfrac{5}{3}}$.

$a^{m}a^{n} = a^{m + n}$.

$\left( {ab} \right)^{n} = a^{n}b^{n}$.

$\left( a^{m} \right)^{n} = a^{mn}$.

$a^{m}b^{n} = \left( {ab} \right)^{m + n}$.

$5$.

$\dfrac{1}{5}$.

$- 5$.

$- \dfrac{1}{5}$.

$\log_{a}\left( {a^{5}b^{3}} \right) = 5 + 3\log_{a}b$.

$\log_{a}\left( {a^{5}b^{3}} \right) = 5 + \log_{a}b$.

$\log_{a}\left( {a^{5}b^{3}} \right) = \dfrac{5}{3} + \log_{a}b$.

$\log_{a}\left( {a^{5}b^{3}} \right) = \dfrac{1}{5} + \dfrac{1}{3}\log_{a}b$.

$y = x^{\sqrt{5}}$.

$y = x^{\log 3}$.

$y = \log_{2}x$.

$y = \left( \dfrac{\pi}{4} \right)^{x}$.

$x = 5$.

$x = \dfrac{1}{5}$.

$x = - 5$.

$x = - \dfrac{1}{5}$.

$45^{0}$.

$60^{0}$.

$90^{0}$.

$0^{0}$.

$AC\bot\left( {SAD} \right)$.

$AB\bot\left( {SAD} \right)$.

$BC\bot\left( {SAD} \right)$.

$BD\bot\left( {SAD} \right)$.

Nếu b // a thì $b\bot(P)$.

Nếu $b \subset (P)$ thì $b\bot a$.

Nếu b // (P) thì $b\bot a$.

Nếu b // a thì b // (P).

A.

B.

C.

D.

$\left( {SBC} \right)\bot\left( {ABCD} \right)$.

$\left( {SAB} \right)\bot\left( {ABCD} \right)$.

$\left( {SAD} \right)\bot\left( {ABCD} \right)$.

$\left( {SAC} \right)\bot\left( {ABCD} \right)$.

$\widehat{SCA}$.

$\widehat{SBA}$.

$\widehat{SBC}$.

$\widehat{SAB}$.