Đề giữa kì 1 Toán 11 năm 2025 – 2026 trường THPT số 1 Lê Hồng Phong – Đắk Lắk

$\dfrac{3}{5}$.

$- \dfrac{3}{5}$.

$- \dfrac{1}{5}$.

$\dfrac{1}{5}$.

Song song.

Chéo nhau.

Cắt nhau.

Trùng nhau.

$y = \cos x$.

$y = \tan x$.

$y = \cot x$.

$y = \sin x$.

$D = R\backslash\left\{ {2k\pi,\, k \in {\mathbb{Z}}} \right\}$.

$D = R\backslash\left\{ {\dfrac{\pi}{2} + k\pi,\, k \in {\mathbb{Z}}} \right\}$.

$D = R\backslash\left\{ {\dfrac{k\pi}{2},\, k \in {\mathbb{Z}}} \right\}$.

$D = R\backslash\left\{ {k\pi,\, k \in {\mathbb{Z}}} \right\}$.

$\cos\left( {a + b} \right) = \cos a\,.\cos b + \sin a.\,\sin b$.

$\cos\left( {a - b} \right) = \cos a\,.\cos b + \sin a.\,\sin b$.

$\sin\left( {a - b} \right) = \sin a.\,\cos b + \cos a.\,\sin b$.

$\sin\left( {a + b} \right) = \sin a.\,\cos b - \cos a.\,\sin b$.

BC, AD cùng nằm trong một mặt phẳng.

BC, AD song song.

BC, AD cắt nhau.

BC, AD chéo nhau.

$\left\{ {\pm \dfrac{2\pi}{3} + k2\pi\,,\,\, k \in {\mathbb{Z}}} \right\}.$

$\left\{ {\,\dfrac{\pi}{3} + k2\pi\,,\,\, k \in {\mathbb{Z}}} \right\}.$

$\left\{ {\pm \dfrac{\pi}{3} + k2\pi\,,\,\, k \in {\mathbb{Z}}} \right\}.$

$\left\{ {\pm \dfrac{\pi}{6} + k2\pi,\, k \in {\mathbb{Z}}} \right\}.$

$1; - 2; - 4; - 6; - 8$.

$1; - 3; - 5; - 7; - 9$.

$1; - 3; - 7; - 11; - 15$.

$1; - 3; - 6; - 9; - 12$.

OM // (SAB).

OM // (SBC).

OM // (SAC).

OM // (SAD).

AM.

SM.

AC.

SA.

$T = \pi$.

$T = 6\pi$.

$T = 2\pi$.

$T = 3\pi$.

$\dfrac{\pi}{4}$.

$\dfrac{3\pi}{5}$.

$\dfrac{\pi}{10}$.

$\dfrac{3\pi}{2}$.