Đề cuối kỳ 1 Toán 10 năm 2024 – 2025 trường THPT chuyên Trần Phú – Hải Phòng

$\overset{\rightarrow}{IB} = - \dfrac{4}{3}\overset{\rightarrow}{AB}$.

$\overset{\rightarrow}{IB} = \dfrac{4}{3}\overset{\rightarrow}{AB}$.

$\overset{\rightarrow}{IB} = 3\overset{\rightarrow}{IA}$.

$\overset{\rightarrow}{IB} = - 3\overset{\rightarrow}{IA}$.

$\overset{\rightarrow}{AB}.\overset{\rightarrow}{AC} = - \dfrac{a^{2}}{2}$.

$\overset{\rightarrow}{AB}.\overset{\rightarrow}{AC} = \dfrac{a^{2}}{2}$.

$\overset{\rightarrow}{AB}.\overset{\rightarrow}{AC} = - \dfrac{a^{2}\sqrt{3}}{2}$.

$\overset{\rightarrow}{AB}.\overset{\rightarrow}{AC} = 2a^{2}.$

$AC = 4\sqrt{3}$.

$AC = 3\sqrt{3}$.

$AC = \sqrt{3}$.

$AC = 2\sqrt{3}$.

$\pm \dfrac{\sqrt{5}}{5}.$

$- \dfrac{\sqrt{5}}{2}.$

$- \dfrac{\sqrt{5}}{5}.$

$\dfrac{\sqrt{5}}{5}.$

4.

$\sqrt{13}$.

$2\sqrt{13}$.

8.

$\alpha = 45^{\text{o}}$.

$\alpha = 180^{\text{o}}$.

$\alpha = 90^{\text{o}}$.

$\alpha = 0^{\text{o}}$.

$(1;3\rbrack$.

$( - \infty;5\rbrack$.

$( - \infty;1)$.

$\left( {3;5} \right\rbrack$.

$a^{2} = b^{2} + c^{2} + 2bc\cos A$.

$\cos B = \dfrac{a^{2} + c^{2} - b^{2}}{2ac}$.

$a^{2} = b^{2} + c^{2} - 2bc\cos A$.

$\cos A = \dfrac{b^{2} + c^{2} - a^{2}}{2bc}$.

2.

6.

4.

8.

$\overset{\rightarrow}{a} = \left( {4; - 1} \right)$.

$\overset{\rightarrow}{a} = \left( {- 1; - 4} \right)$.

$\overset{\rightarrow}{a} = \left( {- 1;4} \right)$.

$\overset{\rightarrow}{a} = \left( {- 4;1} \right)$.

$\left\{ \begin{array}{l} {x + \sqrt{y} \gt 3} \\ {x - y \geq - 2} \end{array} \right..$

$\left\{ \begin{array}{l} {3x^{2} - 20y \gt 7} \\ {x + y^{2} \leq 100} \end{array} \right..$

$\left\{ \begin{array}{l} {x \gt \, 5} \\ {y + \, 2 \lt \, 0} \\ {x + \, y\, \geq 100} \end{array} \right..$

$\left\{ \begin{array}{l} {x + \, y + \, z \lt \, 10} \\ {x + \, y\, \lt \, 5} \\ {2x\, + \, 3y \geq \, 20} \end{array} \right..$

$\left\{ a \right\} \in S$.

$a \subset S$.

$S \supset a$.

$a \in S$.

$\overset{\rightarrow}{OB} - \overset{\rightarrow}{OC} = \overset{\rightarrow}{OD} - \overset{\rightarrow}{OA}.$

$\overset{\rightarrow}{OA} - \overset{\rightarrow}{OB} = \overset{\rightarrow}{CD}.$

$\overset{\rightarrow}{BC} - \overset{\rightarrow}{BA} = \overset{\rightarrow}{DC} - \overset{\rightarrow}{DA}.$

$\overset{\rightarrow}{AB} - \overset{\rightarrow}{AD} = \overset{\rightarrow}{DB}.$

$\left| \overset{\rightarrow}{AB} \right| = \left| \overset{\rightarrow}{BA} \right|$.

Vectơ $\overset{\rightarrow}{0}$ cùng hướng với mọi vectơ.

$\overset{\rightarrow}{AA} = 0$.

Vectơ $\overset{\rightarrow}{0}$ cùng phương với mọi vectơ.

$\tan\alpha \gt 0$.

$\cot\alpha \gt 0$.

$\sin\alpha \gt 0$.

$\cos\alpha \gt 0$.