Tính: B=1,2.(313−2,2)−215.(−2+56)−20220B = 1,2.(3\frac{1}{3} - 2,2) - \frac{2}{{15}}.( - 2 + \frac{5}{6}) - {2022^0}B=1,2.(331−2,2)−152.(−2+65)−20220
1
116225\frac{{116}}{{225}}225116
46225\frac{{46}}{{225}}22546
0
Đáp án: <p><span data-type="math-inline" data-latex="\frac{{116}}{{225}}">$\frac{{116}}{{225}}$</span></p>
Phương pháp giải:
Tính các biểu thức trong ngoặc trước
Lời giải chi tiết:
B=1,2.(313−2,2)−215.(−2+56)−20220=1210.(103−115)−215.(−126+56)−1=65.(5015−3315)−215.(−76)−1=65.1715+745−1=3425+745−1=306225+35225−225225=116225\begin{array}{l}B = 1,2.(3\frac{1}{3} - 2,2) - \frac{2}{{15}}.( - 2 + \frac{5}{6}) - {2022^0}\\ = \frac{{12}}{{10}}.(\frac{{10}}{3} - \frac{{11}}{5}) - \frac{2}{{15}}.(\frac{{ - 12}}{6} + \frac{5}{6}) - 1\\ = \frac{6}{5}.(\frac{{50}}{{15}} - \frac{{33}}{{15}}) - \frac{2}{{15}}.(\frac{{ - 7}}{6}) - 1\\ = \frac{6}{5}.\frac{{17}}{{15}} + \frac{7}{{45}} - 1\\ = \frac{{34}}{{25}} + \frac{7}{{45}} - 1\\ = \frac{{306}}{{225}} + \frac{{35}}{{225}} - \frac{{225}}{{225}}\\ = \frac{{116}}{{225}}\end{array}B=1,2.(331−2,2)−152.(−2+65)−20220=1012.(310−511)−152.(6−12+65)−1=56.(1550−1533)−152.(6−7)−1=56.1517+457−1=2534+457−1=225306+22535−225225=225116
