Trắc nghiệm Bài 25: Phép cộng và phép trừ phân số Toán 6

$\dfrac{a}{m} + \dfrac{b}{m} = \dfrac{{a - b}}{m}$

$\dfrac{a}{m} + \dfrac{b}{m} = \dfrac{{a.b}}{m}$

$\dfrac{a}{m} + \dfrac{b}{m} = \dfrac{{a + b}}{m}$

$\dfrac{a}{m} + \dfrac{b}{m} = \dfrac{{a + b}}{{m + m}}$

$\dfrac{1}{3}$

$\dfrac{4}{3}$

$\dfrac{3}{4}$

$1$

$\dfrac{{ - 5}}{2}$

$- \dfrac{{29}}{5}$

$\dfrac{{ - 40}}{9}$

$\dfrac{{40}}{9}$

$\dfrac{{ - 4}}{{11}} + \dfrac{7}{{ - 11}} \gt 1$

$\dfrac{{ - 4}}{{11}} + \dfrac{7}{{ - 11}} \lt 0$

$\dfrac{8}{{11}} + \dfrac{7}{{ - 11}} \gt 1$

$\dfrac{{ - 4}}{{11}} + \dfrac{{ - 7}}{{11}} \gt - 1$

$\dfrac{3}{2} + \dfrac{2}{3} \gt 1$

$\dfrac{3}{2} + \dfrac{2}{3} = \dfrac{{13}}{6}$

$\dfrac{3}{4} + \left( {\dfrac{{ - 4}}{{17}}} \right) = \dfrac{{35}}{{68}}$

$\dfrac{4}{{12}} + \dfrac{{21}}{{36}} = 1$

$\dfrac{{12}}{{33}}$

$\dfrac{{177}}{{260}}$

$\dfrac{{187}}{{260}}$

$\dfrac{{177}}{{26}}$

$A \gt 1$

$A = \dfrac{2}{{11}}$

$A = 1$

$A = 0$

$x \in \left\{ {0;1;2;3;4} \right\}$

$x \in \left\{ { - 1;0;1;2;3;4;5} \right\}$

$x \in \left\{ { - 1;0;1;2;3;4} \right\}$

$x \in \left\{ {0;1;2;3;4;5} \right\}$

$4$ giờ

$3$ giờ

$1$ giờ

$2$ giờ

$\dfrac{{ - 13}}{7}$

$\dfrac{{13}}{{ - 7}}$

$- \dfrac{{13}}{7}$

Tất cả các đáp án trên đều đúng

$\dfrac{1}{{10}}$

$\dfrac{4}{5}$

$\dfrac{2}{5}$

$\dfrac{{ - 1}}{{10}}$

$\dfrac{9}{{14}}$

$\dfrac{1}{{14}}$

$\dfrac{{11}}{{14}}$

$\dfrac{1}{2}$

$- \dfrac{5}{{16}}$

$\dfrac{5}{{16}}$

$\dfrac{{19}}{{16}}$

$- \dfrac{{19}}{{16}}$

$2$

$1$

$- 1$

$5$

$\dfrac{1}{{39}}$

$\dfrac{2}{{15}}$

$\dfrac{{ - 2}}{{65}}$

$\dfrac{1}{{15}}$

$\dfrac{{17}}{{40}}$

$\dfrac{1}{{40}}$

$\dfrac{1}{{13}}$

$1$

$\dfrac{73}{84}$

$\dfrac{-13}{84}$

$\dfrac{83}{84}$

$\dfrac{143}{84}$