Đề thi Giữa kì 2 Toán 12 năm 2024-2025 trường THPT Trần Quốc Tuấn (Phú Yên)

$F(x) = x^3 + C$

$F(x) = \dfrac{1}{3}x^3 + C$

$F(x) = 3x^3 + C$

$F(x) = 2x + C$

$\displaystyle \int kf(x)dx = k \displaystyle \int f(x)dx \ (\forall k \in \mathbb{R}\backslash \{0\})$

$\displaystyle \int [f(x).g(x)] dx = \displaystyle \int f(x) dx. \displaystyle \int g(x) dx$

$\displaystyle \int [f(x) + g(x)] dx = \displaystyle \int f(x) dx + \displaystyle \int g(x) dx$

$\displaystyle \int [f(x) - g(x)] dx = \displaystyle \int f(x) dx - \displaystyle \int g(x) dx$

10

7

-3

3

$2.5^{2x} \ln 5 + x + C$

$\dfrac{5^{2x}}{2 \ln 5} + 1 + C$

$\dfrac{5^{2x+1}}{2x+1} + x + C$

$\dfrac{25^x}{2 \ln 5} + x + C$

$F(x) = \sin x + C$

$F(x) = -\cos x + C$

$F(x) = \cos x + C$

$F(x) = -\sin x + C$

$(4; -2; -1)$

$(4; -2; 1)$

$(4; 2; -1)$

$(-8; 5; 0)$

$\int f'(x)\,dx=f(x)+C$

$F(x)=f'(x)$

$\int f(x)\,dx=F(x)+C$

$F'(x)=f(x)$

$O(0;0;0)$

$I(1;0;0)$

$K(0;0;1)$

$J(0;1;0)$

$S=\pi\int_{a}^{b}f^{2}(x)dx$

$S=\left|\int_{a}^{b}f(x)dx\right|$

$S=\int_{a}^{b}\left|f(x)\right|dx$

$S=\int_{a}^{b}f(x)dx$