Đề thi Giữa kì 1 Toán 9 năm 2025-2026 THCS An Lão (Ninh Bình)

$(2;2)$

$\left(1;\dfrac{2}{3}\right)$

$(-1;2)$

$(3;-3)$

$\left\{\begin{matrix}x+3y=2\\31x^2+5y=-1.\end{matrix}\right.$

$\left\{\begin{matrix}x=0\\2x+8y=-15.\end{matrix}\right.$

$\left\{\begin{matrix}x-3y^2=1\\-3x=6.\end{matrix}\right.$

$\left\{\begin{matrix}0,3x-0,2y=-0,4\\0x+0y=-0,2.\end{matrix}\right.$

$3x-2y=5$

$ax - by=c$

$7x=2$

$0x+2y=9$

$45^\circ$

$90^\circ$

$30^\circ$

$60^\circ$

$\dfrac{4}{5}$

$\dfrac{3}{4}$

$\dfrac{4}{3}$

$\dfrac{3}{5}$

$ax + b <0$

$x > 0$

$x \cdot \dfrac{1}{x}<0$

$x-1 > 3x^2+1$

$8 - a \le 8 - b$

$a - 8 \ge b - 8$

$-4a \ge -4b$

$5a \ge 5b$